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Reasoning MCQ with Answers

20 questionswith explanationsfor RAS, Patwari, VDO and other Rajasthan exams

Questions

Q1

In a certain language DEBU is coded as 45221 and MANSI is coded as 13114199. In the same language RAJVEER is coded as -

  1. (1)16100225588
  2. (2)17111222555
  3. (3)18011252581
  4. (4)18110225518

Answer: (4) 18110225518

Explanation

Each letter is written as its place in the alphabet: DEBU = 4, 5, 2, 21 and MANSI = 13, 1, 14, 19, 9. RAJVEER = 18, 1, 10, 22, 5, 5, 18, that is 18110225518.

Q2

Find the next term of the following series - ADA, EHE, ILI, ....................

  1. (1)JKJ
  2. (2)GJG
  3. (3)MPM
  4. (4)JHJ

Answer: (3) MPM

Explanation

The outer letters go A, E, I, M (+4) and the middle letters D, H, L, P (+4), so the next term is MPM.

Q3

Insert the missing number in the following - (Figure: three figures, each with two numbers on top joined to one number below: (1) 20 and 75 over 35 (2) 30 and 55 over 41 (3) ? and 85 over 67)

  1. (1)35
  2. (2)40
  3. (3)45
  4. (4)50

Answer: (4) 50

Explanation

The lower number = left number + one-fifth of the right number: 20 + 75 ÷ 5 = 35 and 30 + 55 ÷ 5 = 41. So ? + 85 ÷ 5 = 67 gives ? = 67 − 17 = 50.

Q4

Identify the number that fits in the given pattern - 16, 81, 256, 625, 1296, ………….

  1. (1)2401
  2. (2)2405
  3. (3)2409
  4. (4)2415

Answer: (1) 2401

Explanation

The terms are fourth powers: 2⁴, 3⁴, 4⁴, 5⁴, 6⁴. The next is 7⁴ = 2401.

Q5

In the following question, find out the missing number - (Figure: eight numbers in circles round a wheel, clockwise from the top: 16, 17, 19, 22, 26, ?, 37, 42)

  1. (1)30
  2. (2)25
  3. (3)27
  4. (4)31

Answer: (4) 31

Explanation

Going clockwise from 16, the numbers rise by 1, 2, 3, 4, 5, 6: 16, 17, 19, 22, 26, 31, 37, so the missing number is 26 + 5 = 31. The last step, 37 to 42, is +5 instead of +7, but no other option fits the first steps: 30, 25 and 27 do not give +5 after 26.

Q6

Complete the following series - 5040, 720, 120, 24, ............, 2, 1

  1. (1)8
  2. (2)7
  3. (3)6
  4. (4)5

Answer: (3) 6

Explanation

The terms are factorials: 7! = 5040, 6! = 720, 5! = 120, 4! = 24, so the gap is 3! = 6, followed by 2! = 2 and 1! = 1.

Q7

If ‘+’ means ‘×’, ‘–’ means ‘+’, ‘×’ means ‘÷’ and ‘÷’ means ‘–’, then – 20 + 10 × 20 ÷ 4 – 10 has a value of -

  1. (1)8
  2. (2)16
  3. (3)32
  4. (4)17

Answer: (2) 16

Explanation

Replacing the signs gives 20 × 10 ÷ 20 − 4 + 10. Division and multiplication first: 200 ÷ 20 = 10, then 10 − 4 + 10 = 16.

Q8

If E = 5 and BAT = 23, then MUG = …………….

  1. (1)41
  2. (2)53
  3. (3)57
  4. (4)62

Answer: (1) 41

Explanation

Each word is the sum of its letters' places in the alphabet: BAT = 2 + 1 + 20 = 23. So MUG = 13 + 21 + 7 = 41.

Q9

Find out the missing number - (Figure: three circles, each divided into three parts with a number on top and two below: (1) 5 on top, 3 and 4 below (2) 10 on top, 6 and 8 below (3) ? on top, 9 and 12 below)

  1. (1)15
  2. (2)18
  3. (3)20
  4. (4)13

Answer: (1) 15

Explanation

The top number is √(a² + b²) of the two lower numbers: √(9 + 16) = 5 and √(36 + 64) = 10. So √(81 + 144) = √225 = 15.

Q10

If ACE = 15 and BDF = 48, then what will be HJL?

  1. (1)960
  2. (2)710
  3. (3)698
  4. (4)250

Answer: (1) 960

Explanation

Multiply the letters' places in the alphabet: ACE = 1 × 3 × 5 = 15 and BDF = 2 × 4 × 6 = 48. So HJL = 8 × 10 × 12 = 960.

Q11

If ‘blue’ is called ‘green’, ‘green’ is called ‘white’, ‘white’ is called ‘red’, ‘red’ is called ‘black’, then what is the color of clear sky?

  1. (1)Blue
  2. (2)Green
  3. (3)White
  4. (4)Black

Answer: (2) Green

Explanation

A clear sky is blue, and in this code blue is called green. So the answer is green.

Q12

If VOTER = 41352, HEATER = 743654, TEASER = 645834, then which number represents “S”?

  1. (1)1
  2. (2)5
  3. (3)8
  4. (4)7

Answer: (3) 8

Explanation

HEATER and TEASER share the letters T, E, A, E, R and differ only in H and S. Their digits share 3, 4, 4, 5, 6 and differ only in 7 and 8. So H = 7 and S = 8.

Q13

Which one will replace the question mark? A₁ B₅ C₉ D₁₃ E₁₇ ? G₇ H₁₁ I₁₅

  1. (1)F₂₁
  2. (2)G₂₂
  3. (3)H₂₃
  4. (4)I₂₄

Answer: (1) F₂₁

Explanation

The letters run A to I in order, so the missing letter is F. In each row the numbers rise by 4: 13, 17, 21. So the answer is F₂₁.

Q14

Find the next term in the following series - 3F, 6G, 11I, 18L, ……….

  1. (1)21O
  2. (2)25N
  3. (3)25P
  4. (4)27P

Answer: (4) 27P

Explanation

The numbers 3, 6, 11, 18 rise by 3, 5, 7, so next is 18 + 9 = 27. The letters F, G, I, L move 1, 2, 3 places, so next is L + 4 = P. The term is 27P.

Q15

How many letters of the English alphabet lie between the 9th letter from the beginning and the 9th letter from the end?

  1. (1)7
  2. (2)8
  3. (3)9
  4. (4)10

Answer: (2) 8

Explanation

The 9th letter from the beginning is I (position 9) and the 9th from the end is R (position 26 − 9 + 1 = 18), so the letters between them are J to Q, i.e. 18 − 9 − 1 = 8. The answer 9 comes from forgetting to leave out R itself.

Q16

In a knock-out badminton tournament 24 players take part. Every match has one winner who moves ahead and one loser who is out. How many matches must be played to decide the champion?

  1. (1)12
  2. (2)22
  3. (3)23
  4. (4)24

Answer: (3) 23

Explanation

Each match removes exactly one player, and 23 of the 24 must be removed to leave one champion, so 23 matches are needed (players − 1). The figure 12 is only the number of first-round matches.

Q17

How many letters of the word PLANET remain in the same position when its letters are arranged in alphabetical order?

  1. (1)0
  2. (2)1
  3. (3)2
  4. (4)3

Answer: (3) 2

Explanation

Alphabetical order gives AELNPT against PLANET; only N (4th place) and T (6th place) stay where they were, so the count is 2. P, L, A and E all move.

Q18

Starting from the bottom, a snail climbs 4 m up a 12 m wall every day and slips back 2 m every night. On which day does it first reach the top of the wall?

  1. (1)5th day
  2. (2)6th day
  3. (3)4th day
  4. (4)3rd day

Answer: (1) 5th day

Explanation

Each full day and night adds a net 2 m, so after 4 days and nights it is at 8 m; on the 5th day it climbs 4 m to 12 m and reaches the top before it can slip. Dividing 12 by 2 to get 6 days forgets that it does not slip after reaching the top.

Q19

At a village fair, 3 kg of rice is exchanged for 2 kg of sugar, and 4 kg of sugar for 10 kg of wheat flour. How many kg of wheat flour can be had for 12 kg of rice?

  1. (1)8 kg
  2. (2)30 kg
  3. (3)45 kg
  4. (4)20 kg

Answer: (4) 20 kg

Explanation

12 kg of rice gives 12 × 2 ÷ 3 = 8 kg of sugar, and 8 kg of sugar gives 8 × 10 ÷ 4 = 20 kg of flour. Stopping at 8 kg gives only the sugar, and 30 kg treats the 12 kg of rice as if it were sugar.

Q20

Which set of signs, put in order in place of the three *, makes the equation correct (follow BODMAS)? 24 * 6 * 2 * 3 = 20

  1. (1)−, ×, ÷
  2. (2)+, ÷, −
  3. (3)−, ÷, ×
  4. (4)÷, +, ×

Answer: (1) −, ×, ÷

Explanation

With −, ×, ÷ the expression is 24 − 6 × 2 ÷ 3 = 24 − 4 = 20 (multiplication and division first). The set −, ÷, × gives 24 − (6 ÷ 2) × 3 = 15, and +, ÷, − gives 24.