Q1
What is the average of 12, 15, 18, 21 and 24?
- (1)16
- (2)18✓ Correct answer
- (3)19
- (4)20
Answer: (2) 18
Explanation
Sum = 90, count = 5, average = 18.
20 questionswith explanationsfor RAS, Patwari, VDO and other Rajasthan exams
What is the average of 12, 15, 18, 21 and 24?
Answer: (2) 18
Explanation
Sum = 90, count = 5, average = 18.
What is the arithmetic mean of 4, 8, 12, 16 and 20?
Answer: (1) 12
Explanation
Mean = (4 + 8 + 12 + 16 + 20) ÷ 5 = 60 ÷ 5 = 12.
What is the mode of the data: 2, 3, 4, 3, 5, 3, 4?
Answer: (3) 3
Explanation
3 occurs most often (3 times), so the mode is 3.
What is 20% of 250?
Answer: (4) 50
Explanation
20% of 250 = 250 × 20/100 = 50.
What is the simple interest on ₹5,000 at 8% per annum for 3 years?
Answer: (1) ₹1,200
Explanation
SI = P × R × T / 100 = 5000 × 8 × 3 / 100 = ₹1,200.
What is the median of 7, 3, 9, 5, 11, 1?
Answer: (3) 6
Explanation
Arranged: 1, 3, 5, 7, 9, 11. Median = (5 + 7) ÷ 2 = 6.
If the price of sugar rises by 25%, by what percentage must a family reduce its consumption so that its expenditure on sugar remains unchanged?
Answer: (2) 20%
Explanation
Reduction = 25/(100 + 25) × 100 = 20%.
₹1,200 is divided between A and B in the ratio 3 : 5. What is B's share?
Answer: (1) ₹750
Explanation
B's share = 1200 × 5/8 = ₹750.
The average of 5 numbers is 20. If one number is removed, the average of the remaining numbers becomes 18. What is the removed number?
Answer: (2) 28
Explanation
Removed number = 5 × 20 − 4 × 18 = 100 − 72 = 28.
What is the compound interest on ₹10,000 at 10% per annum for 2 years, compounded annually?
Answer: (3) ₹2,100
Explanation
Amount = 10000 × (1.1)² = ₹12,100; CI = 12,100 − 10,000 = ₹2,100.
Two successive discounts of 20% and 10% are equivalent to a single discount of:
Answer: (4) 28%
Explanation
Single discount = 20 + 10 − (20 × 10)/100 = 28%.
In a moderately skewed distribution, the mean is 30 and the median is 32. Using the empirical relation, what is the mode?
Answer: (2) 36
Explanation
Mode = 3 × Median − 2 × Mean = 96 − 60 = 36.
The present ages of A and B are in the ratio 4 : 5. After 5 years, the ratio will be 5 : 6. What is A's present age?
Answer: (4) 20 years
Explanation
(4x + 5)/(5x + 5) = 5/6 ⇒ 24x + 30 = 25x + 25 ⇒ x = 5; A = 4 × 5 = 20 years.
What is the median of the data: 12, 7, 15, 9, 20, 11, 18?
Answer: (2) 12
Explanation
Arranged in order: 7, 9, 11, 12, 15, 18, 20; the 4th (middle) value is 12.
What is the range of the data: 34, 18, 52, 27, 41, 19?
Answer: (4) 34
Explanation
Range = largest − smallest = 52 − 18 = 34.
Class A has 30 students with average marks 60, and class B has 20 students with average marks 70. What is the average marks of all 50 students taken together?
Answer: (3) 64
Explanation
Weighted average = (30 × 60 + 20 × 70)/50 = 3200/50 = 64.
The mean of 10 observations is 25. It was later found that one observation, 34, was wrongly copied as 43. What is the correct mean?
Answer: (4) 24.1
Explanation
Correct sum = 250 − 43 + 34 = 241; correct mean = 241/10 = 24.1.
What is the standard deviation (population) of the data: 2, 4, 4, 4, 5, 5, 7, 9?
Answer: (2) 2
Explanation
Mean = 40/8 = 5; sum of squared deviations = 32; variance = 32/8 = 4; SD = √4 = 2.
Two fair dice are thrown together. What is the probability that the sum of the numbers obtained is 7?
Answer: (2) 1/6
Explanation
Favourable pairs: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6 out of 36, so P = 6/36 = 1/6.
One card is drawn at random from a well-shuffled pack of 52 playing cards. What is the probability that it is either a king or a heart?
Answer: (3) 4/13
Explanation
P = 4/52 + 13/52 − 1/52 (king of hearts counted twice) = 16/52 = 4/13.